110=80t^2

Solution for 110=80t^2 equation:

110=80t^2

We move all terms to the left:

110-(80t^2)=0

a = -80; b = 0; c = +110;
Δ = b2-4ac
Δ = 02-4·(-80)·110
Δ = 35200
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{35200}=\sqrt{1600*22}=\sqrt{1600}*\sqrt{22}=40\sqrt{22}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-40\sqrt{22}}{2*-80}=\frac{0-40\sqrt{22}}{-160}
=-\frac{40\sqrt{22}}{-160}
=-\frac{\sqrt{22}}{-4}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+40\sqrt{22}}{2*-80}=\frac{0+40\sqrt{22}}{-160}
=\frac{40\sqrt{22}}{-160}
=\frac{\sqrt{22}}{-4}
$